entries

entries()

Try it

Object.entries()方法返回一个给定对象自身可枚举属性的键值对数组，其排列与使用 for...in 循环遍历该对象时返回的顺序一致（区别在于 for-in 循环还会枚举原型链中的属性）。

const object1 = {
  a: "somestring",
  b: 42,
};

for (const [key, value] of Object.entries(object1)) {
  console.log(`${key}: ${value}`);
}

// expected output:
// "a: somestring"
// "b: 42"

语法

Object.entries(obj);

参数

obj 可以返回其可枚举属性的键值对的对象。

返回值

给定对象自身可枚举属性的键值对数组。

Example

const obj = { foo: "bar", baz: 42 };
console.log(Object.entries(obj)); // [ ['foo', 'bar'], ['baz', 42] ]

// array like object
const obj = { 0: "a", 1: "b", 2: "c" };
console.log(Object.entries(obj)); // [ ['0', 'a'], ['1', 'b'], ['2', 'c'] ]

// array like object with random key ordering
const anObj = { 100: "a", 2: "b", 7: "c" };
console.log(Object.entries(anObj)); // [ ['2', 'b'], ['7', 'c'], ['100', 'a'] ]

// getFoo is property which isn't enumerable
const myObj = Object.create(
  {},
  {
    getFoo: {
      value() {
        return this.foo;
      },
      \
    },
  }
);
myObj.foo = "bar";
console.log(Object.entries(myObj)); // [ ['foo', 'bar'] ]

// non-object argument will be coerced to an object
console.log(Object.entries("foo")); // [ ['0', 'f'], ['1', 'o'], ['2', 'o'] ]

// iterate through key-value gracefully
const obj = { a: 5, b: 7, c: 9 };
for (const [key, value] of Object.entries(obj)) {
  console.log(`${key} ${value}`); // "a 5", "b 7", "c 9"
}

// Or, using array extras
Object.entries(obj).forEach(([key, value]) => {
  console.log(`${key} ${value}`); // "a 5", "b 7", "c 9"
});