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js 从 url 中获取指定参数

当前 url: https://a.b.com?name=John&gender=male 调用方法：getParamFromUrl('name') // John

正则表达式​

split 拆分法 (代码较复杂，较易理解)​

let url = 'https://a.b.com?name=John&gender=male'

function getParamFromUrl(name) {
  let urlList = url.split('&') //split拆分为数组
  let newList = {}
  let result = ''

  for (let i = 0; i < urlList.length; i++) {
    if (urlList[i].indexOf('?') > -1) {
      let markIndex = urlList[i].indexOf('?') + 1
      let startString = urlList[i].substr(markIndex).split('=') //substr减法：从前开始减法
      newList[startString[0]] = startString[1]
    } else {
      let endString = urlList[i].split('=')
      newList[endString[0]] = endString[1]
    }
  }

  for (let data in newList) {
    if (name === data) {
      result = newList[data]
      console.log(result)
      return result
    }
  }
}

getParamFromUrl('name') // John

参考文章：https://www.jianshu.com/p/708c915fb905